What does a Linear Current Booster do?
The following is courtesy of Solar Converters, Inc.
At times when the sun is non optimum, a Linear Current Booster boosts the current in the pump motor to produce the torque to turn the pump motor. It does this by sacrificing voltage on motor, hence the motor runs slower. This results in a motor that may be pumping slower (there is after all less solar power), but this is better than having a stalled pump pumping nothing which would happen if solar direct.
The net gain varies with pump type and we have heard conflicting numbers everywhere from 30 % to 100 % more water pumped. This is likely more of a function of torque requirement vrs. size of panel. If you put enough solar panels on to supply enough current all day (expensive), you will not see much gain. If you size the panels to match the motor torque requirement, (fewer panels = less cost), a gain of over 50 % is not unrealistic. If the panel is under sized compared to the motor, the gain is 100 % as the pump will not pump at all, but will run with a Linear Current Booster.
Why does this happen?
In a motor, basically the current represents the torque, and the voltage represents the the speed of the motor. Note, a DC motor produces torque even when not rotating.
To illustrate, let us assume it takes 3 amps of current to produce enough torque to turn the pumping mechanism and we have 3.5 amp panels - say approx. 60 W panels.
In the morning when solar direct, there must be enough sunshine to produce the 3 amps of current. With a 3.5 amp panel this will happen at approx. 11.00 a.m. in the morning. When the panel can produce 3 amps of current the motor will start to turn, and pumping will start at whatever voltage (speed) the panel can support the 3 amps of current (or above).
In the morning with a Linear Current Booster, the solar panel voltage is not tied to the motor. Nothing happens until the panel voltage hits approx. 15 V at no current. Then current is available. The motor current starts to rise. BUT the motor is stalled meaning zero motor volts. However, there is winding and wire loss, usually 1 volt worth at 3 amps of current.
As the current in the motor rises to 3 amps and pumping starts, the question is HOW much current is required of the solar panel to support this current in the motor?
If the output voltage is 1 V and the input is at 15 V, the output is 1/15th the input in voltage. For Power in = Power out (neglecting the approx. 4 % loss), the output current must be 15X the input, or conversely THE PANEL CURRENT MUST BE 1/15th the output. If it takes 3 amps to run the motor at 1 V it takes only 3/15 = 0.2 amps of panel current at the panel 15 V. At what time of day is 0.2 amps available from a 3.5 amp panel? - likely about 8:00 a.m. in the morning.
The motor illustrated starts pumping at 8:00 am instead of 11:00 am.
Conversely, the solar direct will stop pumping when the panel cannot produce 3 amps, likely about 4:00 pm and the boosted motor will stop when the panel cannot produce the 0.2 amps, likely say 8:00 pm.
During optimum sun there is little or no difference in pump performance.
Clearly the motor is pumping a lot longer during the day equates to a lot more water pumped! In this example the pump solar direct starts at 11:00 am and stops at 4:00 pm, while the boosted motor runs from 8:00 am to 8:00 pm.
What size of Linear Current Boosters do we make?
We make a large selection of models. Higher current models are also available on special order.